$125\left(\sqrt5\right)^{2x}=1$ হলে $x$ এর মান কত?Options :
$125\left(\sqrt5\right)^{2x}=1$বা, $125 \times 5^{\frac{1}{2} \times 2x}=1$ [ $\because \sqrt a = a^{\frac12}$ ]বা, $125 \times 5^x=1$বা, $5^3 \times 5^x=1$বা, $5^{3+x}=5^0$বা, $3+x=0$$\therefore$ $x=-3$
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